ln(x^2+x-20)-ln(x+5)=1

Solution for ln(x^2+x-20)-ln(x+5)=1 equation:

Simplifying
ln(x2 + x + -20) + -1ln(x + 5) = 1

Reorder the terms:
ln(-20 + x + x2) + -1ln(x + 5) = 1
(-20 * ln + x * ln + x2 * ln) + -1ln(x + 5) = 1
(-20ln + lnx + lnx2) + -1ln(x + 5) = 1

Reorder the terms:
-20ln + lnx + lnx2 + -1ln(5 + x) = 1
-20ln + lnx + lnx2 + (5 * -1ln + x * -1ln) = 1
-20ln + lnx + lnx2 + (-5ln + -1lnx) = 1

Reorder the terms:
-20ln + -5ln + lnx + -1lnx + lnx2 = 1

Combine like terms: -20ln + -5ln = -25ln
-25ln + lnx + -1lnx + lnx2 = 1

Combine like terms: lnx + -1lnx = 0
-25ln + 0 + lnx2 = 1
-25ln + lnx2 = 1

Solving
-25ln + lnx2 = 1

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Reorder the terms:
-1 + -25ln + lnx2 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + -25ln + lnx2 = 0

The solution to this equation could not be determined.